Core Concepts: Voltage, Current, Resistance, and Charge

What This Investigation Is Actually About

When physicists investigate the relationship between current and potential difference in a circuit, they are testing one specific claim: that for a conductor at constant temperature, the current flowing through it is directly proportional to the potential difference across it. That claim is Ohm’s Law. The investigation either confirms it (if you get a straight line through the origin on your V-I graph) or challenges it (if you don’t). Everything else — the equipment, the method, the calculations, the graph analysis — serves that one purpose.

Before any experiment or assignment makes sense, four quantities need to be clear. Not vaguely familiar — actually clear. Because most errors students make in this topic trace back to mixing up what these quantities are, what units they use, and how they relate to each other.

V Potential Difference Measured in volts (V). The “push” that drives charge around a circuit. Also called voltage.
I Current Measured in amperes (A). The rate at which charge flows past a point in the circuit.
R Resistance Measured in ohms (Ω). How much a component opposes the flow of current.
Q Charge Measured in coulombs (C). The total amount of electrical charge that passes a point over time.

The relationship between them is not complicated. Current is charge moving. Potential difference is what makes it move. Resistance is what slows it down. Most of the maths in this topic is just manipulating the two equations that connect these four quantities — V = IR and Q = It.

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Potential Difference (Voltage)

The energy transferred per unit charge. Think of it as the electrical “pressure” that pushes current around. Measured with a voltmeter, connected in parallel.

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Current

The flow of charge carriers (electrons in a wire). One ampere means one coulomb of charge passes per second. Measured with an ammeter, connected in series.

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Resistance

How much a component resists current flow. High resistance = low current for a given voltage. Resistance is what you calculate from the gradient of your V-I graph.

Electric Charge

The total charge that flows through a circuit over time. If you know the current and how long it flows, you can calculate the charge: Q = It.


Ohm’s Law — What V = IR Actually Means

Ohm’s Law states that the potential difference across a conductor is directly proportional to the current flowing through it, provided the temperature remains constant. Written as a formula: V = IR.

That word “proportional” is doing a lot of work. It means: double the voltage, double the current. Halve the voltage, halve the current. The ratio V/I stays constant. That constant ratio is the resistance R. So you can rearrange the formula three ways depending on what you need to find:

Find Voltage
V = I × R
Volts = Amps × Ohms
Use when you know current and resistance
Find Current
I = V ÷ R
Amps = Volts ÷ Ohms
Use when you know voltage and resistance
Find Resistance
R = V ÷ I
Ohms = Volts ÷ Amps
Use when you know voltage and current

The temperature condition matters more than most textbooks emphasise. Resistance in metal conductors increases with temperature. So if you run too much current through a resistor and it heats up mid-experiment, R changes — and Ohm’s Law appears to break down. It hasn’t broken down; the condition just isn’t being met. This is why your investigation should use low currents and take readings quickly.

Worked Example 1 — Finding Resistance
A resistor has a potential difference of 12 V across it and a current of 0.5 A flowing through it. What is its resistance?
R = V ÷ I
Resistance (Ω) = Potential Difference (V) ÷ Current (A)
Step-by-Step Solution

Given: V = 12 V  |  I = 0.5 A
R = 12 ÷ 0.5 = 24 Ω
Check: 24 Ω × 0.5 A = 12 V ✓ The resistor has a resistance of 24 ohms.

Worked Example 2 — Finding Current
A 60 Ω resistor is connected to a 9 V battery. What current flows through it?
I = V ÷ R
Current (A) = Potential Difference (V) ÷ Resistance (Ω)
Step-by-Step Solution

Given: V = 9 V  |  R = 60 Ω
I = 9 ÷ 60 = 0.15 A
Check: 60 Ω × 0.15 A = 9 V ✓ A current of 0.15 amperes flows through the resistor.

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The Triangle Trick — Use It, Then Move Past It

The V-I-R triangle (cover what you want to find; what’s left is the formula) is a useful memory tool at GCSE level. But at A-level and beyond, you need to be able to work from first principles — not just plug numbers in. Markers at higher levels look for evidence that you understand why the formula works, not just that you can use it. When writing up, always state what each variable represents and its unit before substituting values.


Electric Charge Calculation: Q = It — The Key Formula and How to Apply It

Electric charge (Q) is the total amount of electrical charge that passes through a point in a circuit over a period of time. The formula connecting charge, current, and time is one of the most straightforward in physics — and one of the most commonly misapplied, usually because of a unit conversion error with time.

Core Formula — Electric Charge
Q = It  |  Charge = Current × Time
Q = I × t
Q = charge in coulombs (C)  |  I = current in amperes (A)  |  t = time in seconds (s)
Note on Units

Time MUST be in seconds. Convert minutes → seconds by multiplying by 60. Convert hours → seconds by multiplying by 3600.
1 coulomb = 1 ampere flowing for 1 second. That’s the physical meaning of the unit.

Worked Example 3 — The Assignment Question
A current of 2 A flows through a resistor for 5 minutes. Calculate the electric charge that passes through the resistor.
Q = I × t
Identify: I = 2 A  |  t = 5 minutes — MUST convert to seconds first
Full Step-by-Step Solution

Step 1 — Convert time: 5 minutes × 60 = 300 seconds
Step 2 — Substitute into Q = It:
Q = 2 A × 300 s = 600 C
Answer: 600 coulombs of charge pass through the resistor.
Physical interpretation: 600 coulombs is equivalent to approximately 3.75 × 10²¹ electrons — each carrying a charge of 1.6 × 10⁻¹⁹ C.

The single most common error on this type of question is using minutes instead of seconds. The formula Q = It only works when time is in seconds. If you put 5 into the formula instead of 300, you get 10 C — which is wrong by a factor of 60. Always convert time to seconds as your first step, before touching anything else. Write it down explicitly so it’s visible in your working.

More Worked Examples: Building Confidence With Q = It

Worked Example 4 — Finding Time
A charge of 180 C passes through a wire carrying a current of 3 A. How long did this take?
t = Q ÷ I
Rearrange Q = It → t = Q ÷ I
Step-by-Step Solution

Given: Q = 180 C  |  I = 3 A
t = 180 ÷ 3 = 60 seconds (1 minute)
Check: 3 A × 60 s = 180 C ✓

Worked Example 5 — Finding Current
A total charge of 1500 C passes through a circuit in 10 minutes. What is the current?
I = Q ÷ t
Rearrange Q = It → I = Q ÷ t
Step-by-Step Solution

Step 1 — Convert time: 10 minutes × 60 = 600 seconds
I = 1500 ÷ 600 = 2.5 A
Check: 2.5 A × 600 s = 1500 C ✓

GivenFindRearrangementExample
I and t Q (charge) Q = I × t I = 2 A, t = 300 s → Q = 600 C
Q and t I (current) I = Q ÷ t Q = 900 C, t = 300 s → I = 3 A
Q and I t (time) t = Q ÷ I Q = 480 C, I = 4 A → t = 120 s = 2 min

The V-I Experiment: Circuit Setup, Equipment, and Method

This is the standard practical investigation used to verify Ohm’s Law. The goal is to vary the potential difference across a component systematically, measure the resulting current at each voltage, and then plot a V-I graph to see if the relationship is linear. Here is how to set it up properly.

Equipment You Need

EquipmentPurposeConnection
Variable DC power supply (or battery + rheostat) Provides an adjustable potential difference across the circuit Connected to the main circuit loop
Ammeter Measures the current flowing through the component In series — the current flows through it
Voltmeter Measures the potential difference across the component In parallel — it sits across the component being tested
Resistor (or other component under test) The component whose V-I relationship you are investigating In the main circuit loop
Connecting wires and switch Complete the circuit; switch limits heating between readings Switch in series with the component
Rheostat (variable resistor) Allows fine control of current without changing the supply voltage In series with the component under test
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The Ammeter and Voltmeter Positions Are Not Optional

The ammeter goes in series. The voltmeter goes in parallel. These are not stylistic choices — they follow from what each instrument measures. An ammeter measures current flowing through it, so it must be in the path the current takes. A voltmeter measures the potential difference between two points, so it connects across (in parallel with) whatever you are measuring. Swapping them blows ammeters and gives meaningless voltmeter readings. In your circuit diagram and your write-up, the instrument positions must be explicitly correct.

Method: How to Run the Investigation

1

Build and Check the Circuit

Assemble the circuit with the ammeter in series and the voltmeter in parallel across the resistor. Before switching on, check all connections. Keep the switch open until you are ready to take a reading — leaving it closed heats the resistor and changes its resistance.

2

Set Your First Voltage and Take the Reading

Close the switch. Set the supply to your first voltage (e.g., 1 V). Read the ammeter quickly and record both V and I. Open the switch immediately. Record your data in a table with columns for Voltage (V), Current (A), and Resistance R = V/I (Ω).

3

Repeat Across a Range of Voltages

Increase the voltage in regular steps (e.g., 1 V, 2 V, 3 V, 4 V, 5 V). Take a reading at each step. A minimum of six to eight data points gives you enough to draw a meaningful graph. For greater reliability, take repeat readings and average them.

4

Reverse the Connections (If Required)

For a complete V-I characteristic (especially if the component is a diode or bulb), reverse the battery connections to get negative voltage readings. This gives you a symmetric graph around the origin for ohmic conductors.

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Plot Your V-I Graph and Calculate Resistance

Plot potential difference (V) on the y-axis and current (I) on the x-axis. Draw a line of best fit. For an ohmic resistor it will be straight and pass through the origin. The gradient of the line = R (resistance in ohms).

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Why Plot V on the y-Axis and I on the x-Axis?

Convention — and your mark scheme — typically puts V on the y-axis and I on the x-axis. The gradient of this graph gives R directly (since V = IR means gradient = R). Some textbooks reverse this (I on y, V on x), in which case the gradient gives 1/R (conductance). Check your exam board’s specification. If it says “V-I graph,” put V on the vertical axis. If it says “I-V graph,” put I on the vertical axis. The physics is the same; only the gradient interpretation changes.


Plotting and Interpreting the V-I Graph

The graph is where the investigation either confirms or challenges Ohm’s Law. Getting the data collection right matters less if you cannot correctly read what the graph is telling you. Here is what to look for and how to describe it.

Graph ShapeWhat It MeansComponent TypeHow to Calculate R
Straight line through the origin V is directly proportional to I. Ohm’s Law holds. Resistance is constant. Ohmic conductor (e.g., metal resistor at constant temperature) R = gradient = ΔV ÷ ΔI (pick two widely spaced points on the line)
Curve that flattens at higher currents Resistance is increasing as current increases. Temperature is rising, increasing resistance. Filament lamp (non-ohmic) R at any point = V ÷ I at that specific point (not the gradient)
Asymmetric — conducts in one direction only Very low resistance in forward bias; very high resistance in reverse bias. Diode (non-ohmic) R = V ÷ I at any point, but varies enormously with direction
Straight line but NOT through origin There is a systematic error in the experiment — usually an offset in one of the meters, or contact resistance in the circuit. Could be any component — indicates measurement issue Investigate the anomaly; do not force the line through the origin
Worked Example 6 — Calculating Resistance from a Graph Gradient
A V-I graph shows a straight line passing through (0, 0) and (0.4 A, 8 V). What is the resistance?
Gradient = ΔV ÷ ΔI = R
Step-by-Step Solution

Two points: (0, 0) and (0.4, 8)
Gradient = (8 − 0) ÷ (0.4 − 0) = 8 ÷ 0.4 = 20 Ω
The resistor has a resistance of 20 ohms. Verify: V = IR → 0.4 A × 20 Ω = 8 V ✓

The graph does not just show you the answer — it shows you whether the answer is trustworthy. A straight line through the origin with small scatter around it tells you the experiment was well-controlled. A curved or scattered set of points tells you something changed that shouldn’t have.

— Standard guidance in A-level Physics practical skills

What to Write in Your Analysis Section

Three things belong in the analysis of a V-I investigation. First, describe the shape of the graph precisely — do not say “the graph shows the relationship between V and I.” Say whether it is linear, whether it passes through the origin, and whether there are any anomalies. Second, state what the shape tells you about the component (ohmic or non-ohmic, and why). Third, calculate the resistance — either from the gradient (for linear graphs) or from individual V/I pairs (for curves). All three need to be in your write-up to get full marks at any level.


Ohmic vs. Non-Ohmic Components — What the Difference Means

An ohmic conductor is one that obeys Ohm’s Law — its resistance stays constant regardless of the current flowing through it (as long as temperature stays constant). A non-ohmic component has a resistance that changes as conditions change. The distinction is not just exam content; it tells you which components are predictable to use in circuit design and which are not.

Ohmic Conductors

  • Straight V-I graph through the origin
  • Constant resistance at constant temperature
  • Metal wires, most standard resistors
  • V and I increase proportionally
  • R can be calculated from gradient
  • Temperature must stay constant for the law to hold

Non-Ohmic Components

  • Curved V-I graph (filament lamp) or asymmetric (diode)
  • Resistance changes with current, temperature, or light
  • Filament lamps, diodes, thermistors, LDRs
  • V and I do not increase proportionally
  • R must be calculated as V/I at each specific point
  • Their changing resistance is often the useful property (e.g., thermistors in temperature sensors)
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Why Filament Lamps Are Non-Ohmic: The Temperature Explanation

A filament lamp contains a thin tungsten wire. At low voltages, the wire is cool and its resistance is relatively low. As voltage increases, more current flows, the wire heats up — it can reach temperatures above 2,500°C — and resistance increases significantly. So each time you increase the voltage, you get less current than Ohm’s Law would predict for a fixed resistance. The V-I graph curves away from a straight line. The resistance at operating temperature can be ten to fifteen times higher than the cold resistance. This is confirmed in published data from sources such as the Institute of Physics, which maintains extensive practical physics resources for exactly this type of investigation.


Common Mistakes Students Make in V-I Investigations

These are the errors that show up repeatedly in marked scripts and practical reports. Some are experimental. Some are calculation errors. Most are avoidable if you know to watch for them.

ErrorWhy It HappensHow to Avoid It
Using minutes instead of seconds in Q = It Time is given in minutes in the question; students forget to convert Always convert time to seconds as the first written step. Write “t = ___ min × 60 = ___ s” before substituting
Putting the ammeter in parallel and the voltmeter in series Confusion about what each instrument measures and where it goes Ammeter = in series (measures current through it). Voltmeter = in parallel (measures potential difference across). No exceptions.
Calculating gradient using single points instead of two widely spaced points Students pick any two adjacent data points or use a single point divided by the x-axis value Use two points far apart on the line of best fit (not data points). Show the triangle on your graph with ΔV and ΔI labelled.
Saying “the graph shows Ohm’s Law is obeyed” without explaining why Students state the conclusion without the evidence State: the graph is a straight line passing through the origin, which shows V is directly proportional to I, confirming Ohm’s Law at constant temperature
Leaving the switch closed between readings Students don’t realise the continuous current heats the resistor Open the switch between each reading. Only close it while taking the measurement. This keeps temperature approximately constant.
Mixing up R = V/I with R = ΔV/ΔI For ohmic conductors both give the same answer, so the difference isn’t obvious until a non-ohmic component is used For ohmic: use the gradient (ΔV/ΔI). For non-ohmic: use V/I at each specific point — the gradient of a tangent, not the overall slope.

Writing Up Your Lab Report or Assignment: Section by Section

Whether this is a formal lab report, a coursework write-up, or a structured assignment question, the same core structure applies. Each section has a specific job. Get the structure right first, then fill in the physics. If you need expert support with your physics assignment or lab report, Smart Academic Writing’s science specialists can help at all levels.

1

Title and Aim

Short and precise — states exactly what is being investigated

State the investigation clearly. Example: “To investigate the relationship between potential difference and current in an ohmic conductor, and to determine its resistance.” One sentence is enough. Do not pad it. Avoid vague aims like “to learn about circuits” — the aim should be measurable and specific.

2

Hypothesis / Prediction

What do you expect to find, and why?

State your prediction based on theory. Example: “I predict that the current through the resistor will be directly proportional to the potential difference across it, in accordance with Ohm’s Law (V = IR), provided the temperature remains constant. This means the V-I graph will be a straight line passing through the origin, with the gradient equal to the resistance.”

The key is “and why.” A hypothesis without a theoretical basis gets half credit at best. Cite Ohm’s Law by name, state the formula, and link it to the expected graph shape.

3

Method

Reproducible, specific, and honest about controls

List equipment with specifications (e.g., “digital ammeter, range 0–2 A, resolution 0.01 A”). Draw a circuit diagram using standard IEC/BS symbols — not a photograph of the actual circuit. Write the procedure in steps that someone else could follow to reproduce the experiment exactly.

State your independent variable (potential difference — what you change), dependent variable (current — what you measure), and controlled variables (temperature, same resistor, same connections throughout). This is what markers look for when assessing experimental design.

4

Results Table

Organised, correctly headed, with units

Set out a table with: Voltage V (V) | Current I (A) | Resistance R = V/I (Ω). If you took repeat readings, include a column for each repeat and a mean. Units go in the column heading, not in the data cells. Data should be recorded to a consistent number of decimal places that matches your instrument resolution.

Identify any anomalous results. Don’t delete them — mark them clearly and exclude them from your graph and mean calculations, then explain in your evaluation why they are anomalous.

5

Graph

Correctly axes, scaled, and interpreted

V on the y-axis, I on the x-axis. Label both axes with quantity and unit. Scale them so the data occupies at least half the graph area — do not squash everything into one corner. Plot all points. Draw a line of best fit (straight or curved, as the data demands — never connect the dots). Mark any anomalous points clearly but do not include them in the best fit line.

Calculate the gradient: show the triangle on the graph with ΔV and ΔI labelled. State R = gradient = ___ Ω. If the graph is curved (non-ohmic), calculate R at several specific points using R = V/I.

6

Analysis and Conclusion

Link the data back to the physics

State clearly: (a) what the graph shows — describe the shape and whether it is linear; (b) what this means for Ohm’s Law — does the component obey it or not, and how do you know from the graph; (c) the calculated resistance with units; (d) whether the result matches your hypothesis, and if not, why not.

Do not just repeat the results. Interpret them. “The straight line through the origin shows that V is directly proportional to I. This confirms that the resistor is an ohmic conductor and that Ohm’s Law holds at constant temperature. The resistance, calculated from the gradient, is 24 Ω.”

7

Evaluation

Honest assessment of errors, limitations, and improvements

This section is where most students lose marks — either by saying nothing or by listing generic statements like “human error.” Be specific. Identify: systematic errors (e.g., voltmeter draws a small current, causing the ammeter to overread); random errors (e.g., fluctuation in power supply voltage between readings); and limitations (e.g., only six data points — more would give greater confidence in the linear relationship).

For each error, suggest a specific improvement. “Using a higher-impedance voltmeter would reduce the current drawn by the voltmeter itself, improving accuracy.” Examiners want evidence that you understand the physics behind the errors, not just that errors exist.

What Distinguishes a Top-Mark Write-Up

  • The hypothesis cites the theory — Ohm’s Law is stated with the formula, not just described vaguely
  • The circuit diagram uses standard symbols — ammeter in series, voltmeter in parallel, clearly labelled
  • Variables are explicitly identified — independent, dependent, and all controlled variables stated
  • The graph gradient is calculated correctly — large triangle, showing ΔV and ΔI, not using single points
  • The conclusion links back to Ohm’s Law — not just “it was a straight line” but what that line means physically
  • The evaluation identifies specific, named errors — not generic “human error” statements

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FAQs: Current, Potential Difference, and Electric Charge

A current of 2 A flows through a resistor for 5 minutes. What charge passes through?
Use Q = It. Convert time first: 5 minutes × 60 = 300 seconds. Then Q = 2 A × 300 s = 600 C. The most common error is using minutes directly without converting — that gives 10 C, which is wrong by a factor of 60. Always convert time to seconds before substituting into Q = It.
What is the relationship between current and potential difference?
For an ohmic conductor at constant temperature, current is directly proportional to potential difference. That is Ohm’s Law: V = IR. Double the voltage, double the current. The ratio V/I is constant and equals the resistance R. On a V-I graph, this shows up as a straight line through the origin — the gradient equals R. For non-ohmic components (filament lamps, diodes), the relationship is not linear, meaning resistance changes as conditions change.
Where do you connect the ammeter and voltmeter in the circuit?
The ammeter connects in series — it must be in the path the current flows through, because it measures current flowing through it. The voltmeter connects in parallel — it sits across (on either side of) the component being tested, because it measures the potential difference between two points. Connecting them the wrong way round will either blow the ammeter (if connected in parallel, it has very low resistance and draws excessive current) or give a meaningless reading from the voltmeter (if connected in series).
What is the difference between an ohmic and non-ohmic conductor?
An ohmic conductor obeys Ohm’s Law — its resistance stays constant at constant temperature, giving a straight V-I graph through the origin. Examples: metal resistors, copper wire. A non-ohmic component has a resistance that changes as conditions change. A filament lamp’s resistance increases as it heats up (curved V-I graph). A diode allows current only in one direction (asymmetric V-I characteristic). A thermistor’s resistance decreases as temperature increases. For non-ohmic components, you calculate R = V ÷ I at each specific point rather than from the overall gradient.
How do you calculate resistance from a V-I graph?
For a straight-line (ohmic) graph, calculate the gradient: choose two widely spaced points on the line of best fit (not individual data points), then gradient = ΔV ÷ ΔI. That gradient equals the resistance in ohms. For a curved (non-ohmic) graph, you cannot use the overall gradient — instead, calculate R = V ÷ I at each specific data point you want the resistance at. Show your working clearly: mark the two points used for the gradient on the graph itself, draw the triangle, and label ΔV and ΔI.
Why does Ohm’s Law include the condition “at constant temperature”?
Resistance in metal conductors increases with temperature — higher temperature means more lattice vibration in the metal, which impedes electron flow. If temperature rises during an experiment (because the resistor is heating up), R increases, so the V-I relationship is no longer linear even if the component is technically ohmic at any single fixed temperature. The temperature condition is not a loophole — it defines exactly when Ohm’s Law applies. In practical terms, this means taking readings quickly, opening the switch between readings, and using low currents that do not heat the component significantly.
Can Smart Academic Writing help with physics lab reports and circuit assignments?
Yes. The team at Smart Academic Writing includes science specialists who assist with physics coursework write-ups, circuit analysis assignments, lab report structuring, and calculation walkthroughs at GCSE, A-level, and undergraduate level. Support is also available for related areas including academic writing across science subjects, anatomy and physiology homework, and chemistry homework help.

Bringing It Together: What This Investigation Is Really Testing

The V-I investigation looks simple on the surface — connect a resistor, vary the voltage, measure the current, plot a graph. But the marks, at every level, go to students who show they understand the physics behind the procedure. Why is the ammeter in series? Because that’s what measuring current requires. Why does the graph need to pass through the origin? Because V = IR means V = 0 when I = 0. Why must temperature be controlled? Because resistance depends on temperature, and changing R would break the proportionality Ohm’s Law predicts.

The charge calculation follows the same principle. Q = It is a simple formula. But applying it correctly means knowing to convert time to seconds first — every time, without exception. That one step separates a correct answer from one that’s wrong by a factor of 60.

If you need expert support with your physics assignment, lab report, or electric circuits coursework, the science writing team at Smart Academic Writing can help — through academic writing services, lab report writing, and subject-specific homework help across physics, chemistry, and biology.